Question

If O is the centre of a circle, find the value of x in each of the following figures.

Answer 1

Answer:

1. X=130°

2. X= 115°

3. X=50°

4.

1. The X = 110° because AO and AC are radius of same triangle so angle OAC and angle OCA are equal and value is 35°.

SO angle AOC=110°.

Similarly angle ABC= 25° and angle BAC = 25°.

SO angle BOA=120°.

From this we get angle BOC= angle AOB+ angle AOC = 230°

From this we can find the X angle value= 360°-230°=130° {angle at center is 360°}.

2.Draw the bisector on OB so angle X will divided into X/2.

and 130 will also be divided into half that is 65°.

so X/2+angle OAB + 65°= 180° ( Sum of interior angle of triangle)

2 angle OAB = 180°-65°

2 angle OAB = 115°

angle OAB = 115°/2

in the same way as also find other half

and the angle will be 115°/2

Total angle of X= 115/2 ×2= 115°

3.AO=CO radius of same triangle. So the angle CAO = angle OCA= 50°

Value of angle AOC=110°

Angle DOC= 110° (Opposite angel)

and in same way we the value of OBD and angle ODD= 50°.

For question number 4 please provide the angle CBP value clearly.

Answer 2

Answer:

see the answers and take the help of NCERT

Step-by-step explanation:

x =

120

105

50

and last may be 107