If o is the centre of circle and sector OAPB is 5/36 times of area of the circle find the x
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value of x is 50°
•O is center of circle
Given
• ar OAPB = 5/36 ar of circle
ar. OAPB / ar. of circle = 5/36
•also , ar. OAPB / ar. of circle =
<AOB/360°
Where <AOB is angle subtended by segment OAPB at centre of circle.
5/36 = x /360
x = ( 5×360 )/36
x = 50°
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