Math, asked by deepali4009, 7 months ago

If o is the centre of larger circle what is the probability that a point chosen at random within the circumference of the larger circle,lies outside the smaller circle ?
a. 0.33
b. 0.5
c. 0.67
d.0.75​

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Answers

Answered by MaheswariS
8

\textbf{Given:}

\textsf{Radius of the smaller circle is 2 cm}

\textbf{To find:}

\textsf{Probability of choosing a point lies outside the smaller circle}

\textbf{Solution:}

\textsf{From the given figure,}

\textsf{Radius of the larger circle is, R = 4 cm}

\textsf{Radius of the smallerr circle is, r = 2 cm}

\textsf{Let E event of choosing a point out of the smaller circle}

\textsf{within the circumference of the larger circle}

\mathsf{Then,}

\mathsf{P(E)=\dfrac{n(E)}{n(S)}}

\mathsf{P(E)=\dfrac{\textsf{Area outside the smaller circle}}{\textsf{Area of the larger circle}}}

\mathsf{P(E)=\dfrac{\textsf{Area of larger circle-Area of smaller circle}}{\textsf{Area of the larger circle}}}

\mathsf{P(E)=\dfrac{\pi\,R^2-\pi\,r^2}{\pi\,R^2}}

\mathsf{P(E)=\dfrac{\pi\,(4)^2-\pi\,(2)^2}{\pi\,(4)^2}}

\mathsf{P(E)=\dfrac{16\pi-4\pi}{16\pi}}

\mathsf{P(E)=\dfrac{12\pi}{16\pi}}

\mathsf{P(E)=\dfrac{12}{16}}

\mathsf{P(E)=\dfrac{3}{4}}

\implies\boxed{\mathsf{P(E)=0.75}}

\textbf{Answer:}

\textsf{option (d) is correct}

\textbf{Find more:}}

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In a single throw of two dice,the probability of getting doublet i.e. getting the same number on both dice is(a) 1/2

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Answered by vrundghaghra
0

Answer:

option d is correct option.

this is your answer buddy.

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