if o is the centre of the circle angle angle c a b is equals to 50 degree and angle c equals to 90 degree find angle ACB
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here to find angle ACB we just have to find out angle C here a+ o is equal to c {ex.angle is equal to sum of int.opp} a is 50 and o is 90
=50+ 90
= 140
so x or angle c is 140° and ANGLE ACB is also 140° hope u got ur ans
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Answer:
Angle ACB is given already = 90°
x = 50
Step-by-step explanation:
angle ADC = 90°
angle CAD = 50 °
THEREFORE angle ACD = 40 °
SINCE SUM OF ALL ANGLES IN TRIANGLE IS 180°
angle ACB = angle ACD + angle DCB
angle DCB = 50 °
x = 50 °
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