Question

If o is the centre of the circle, find the value of x.

Answer 1

Answer:

50

Step-by-step explanation:

We know that the inscribed angle form in semicircle is always 90.

In triangle ADC,

Angle ACD=40

Angle ACB=Angle ACD+angleDCB

Therefore,

Angle DCB=90-40

Therefore, angle DCB=50

Answer 2

90+50+x= 180 and x=40

Step-by-step explanation:

1. o is the center of the circle

2. at OAC is 50 and AOC =90 BECAUSE right angle

3.COA +COB = 180

90+ COB = 180

COB=180-90

= 90

4.CAO = CBO THEN because alternate interior angles are equal

CAO AND CBO = 50

5.triangle COB = X+90+50= 180

= X + 140= 180

= X = 180-140

= X=40