if O is the centre of the circle, find the value of X in each of the following figure
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Answer:
(i) We have AOC = 135˚
then COB = 180˚ - 135˚ = 45˚
but x = COB/2 = 45˚/2 = 22.1/2˚
(ii) In BOC,
OB = OC
So OCB = OBC = 40˚
In BOC,
BOC = 180 – (40 + 40)˚
= 180˚ – 80˚
So x = BOC/2
= 100˚/2 = 50˚
(iii)
APC = ½ AOC
= ½ × 120˚ = 60˚
Since, ABCD is a cyclic quadrilateral
CBD = x is the exterior angle
So x = APC = 60˚
Answered by
0
Answer:
i) 65°
ii)40°
iii)60°
iv)245°
v)110°
vi)30°
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