Question

if O is the centre of the circle PQ is a chord and PT is a tangent if poq is 70 degree then find the angle TPQ
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Answer 1

Answer:

In the given figure, O is the center of a circle, PQ is a chord and Pt is the tangent at P. If ∠POQ =70o , then ∠TPQ is equal to

We know that the radius and tangent are perpendicular at their point of contact

Since, OP = OQ

POQ is a isosceles right triangle

Now, In isosceles right triangle POQ

angle (poq)+angle (pqo)+ angle (qpo)=180

70+2angle(opq)=180

2angle(opq)=180-70

angle(opq)=110/2

angle(opq)=55

now, angle(tpq)+angle(opq)=90

angle(tpq)=90-55

angle(tpq)=35

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