Question

If o is the centre of the circle; then Find the length of the tangent ab in the given figure ​

Answer 1

Answer:

angle AOC = 90° (Radius is perpendicular at point of contact with tangent) = angle BAC = 65° 25°

therefore , angle AOB = 90°- 65° Now in triangle AOB,

=

=

AO = BO (radius)

therefore angle OAB = angle OBA %3| therefore angle AOB = 180°- (25°x

2)= 130°

Hope it helps!

Answer 2

Given:

In the above figure,

OA = 8 cm

and OB = 10 cm

To find:

length of the tangent AB.

Solution:

Using Pythagoras Theorem, we have

$OB^2 = AB^2 + AO^2\\= > 10^2 = AB^2 +8^2\\= > 100 = AB^2 + 64\\= > AB^2 = 100-64\\= > AB^2 = 36\\= > AB = 6$

Hence, the required value of the tangent AB is 6 cm.