If O is the origin and A and B are points on the line 3x - 4y + 25 = 0 such
that OA OB = 13, then the area of AOAB (in sq.units) is K
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Answer:
Perpendicular distance from origin on the line 3x+4y+15=0 is:
d=
3
2
+4
2
15
=
5
15
=3
OA=9units
Base=2×
9
2
−3
2
=2
72
=12
2
Area=
2
1
×base×height
=
2
1
×12
2
×3
=18
2
units
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