Math, asked by siddhantshinde7777, 2 days ago

If O is the origin and OP,OQ are the tangents from the origin to the circle x 2 +y 2 −6x+4y+8=0, then circumcenter of the triangle OPQ is

Answers

Answered by akamandeepkumar386

OPCQ is cyclic quadrilateral, then circumcircle of ΔOPQ passes through the point C.

Since OP and OQ are tangents to the circle they make perpendicular with CP and CQ respectively. Also a circle inscribes two right angled triangles which are COP and COQ in this case.

Thus for this circle, OC is a diameter, then centre is midpoint of OC

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If O is the origin and OP,OQ are the tangents from the origin to the circle x 2 +y 2 −6x+4y+8=0, then circumcenter of the triangle OPQ is​

Answers

If O is the origin and OP,OQ are the tangents from the origin to the circle x 2 +y 2 −6x+4y+8=0, then circumcenter of the triangle OPQ is