Chemistry, asked by mansichaudhary, 1 year ago

if o2 gas is bubbled through water at 393k​

Answers

Answered by sam42005
0

Explanation:

Acc.to henry's law pO2 = kH .χO2 χO2 = pO2/ kH =0.987/34.86x103 = 2.81 x 10-5 moles of water in 1L =55.5 ­ χO2 = nO2 / nO2 + nH2O = nO2/ nO2+55.5 nO2 =2.81 x 10-5 X 55.5 =1.56 x 10-3mol Solubility of water =1.56 x10-3mol Lit-1 = 1.56 x10-332 g Lit-1 =0.05 g Lit-1

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