If OA = 36 and OP = 60, then the area of kite OAPB is ... .
Answers
Answer:
Correct answer is 1728cm²
Options are not matching because of decimal point.
Step-by-step explanation:
Given :
i) OA = 36 cm
ii) OP = 60 cm
To Find :
Area of kite OAPB
Steps to follow:
1] Find A(ΔOAP)
2] Find A(ΔOBP)
3] Add A(ΔOAP) and A(ΔOBP) = Area of kite OAPB
Solution:
STEP 1]
In ΔOAP,
∠OAP = 90° ...(Tangent theorem)
By Pythagoras' theorem,
OP² = OA²+AP²
60² = 36² + AP²
AP² = 3600 - 1296
AP² = 2304
AP = 48 ...(Taking square root of both sides)
Now,
A(ΔOAP) = 1/2 × Base × Height
= 1/2 × AP × OA
= 1/2 × 48 × 36
A(ΔOAP) = 864 cm²
STEP 2]
In ΔOAP,
∠OBP = 90° ...(Tangent theorem)
OA = OB = 36 cm ...(Radii of same circle)
By Pythagoras' theorem,
OP² = OB²+BP²
60² = 36² + BP²
BP² = 3600 - 1296
BP² = 2304
BP = 48 ...(Taking square root of both sides)
Now,
A(ΔOBP) = 1/2 × Base × Height
= 1/2 × BP × OB
= 1/2 × 48 × 36
A(ΔOBP) = 864 cm²
STEP 3]
Area of kite OAPB = A(ΔOAP) + A(ΔOBP)
= 864 + 864
= 1728 cm²
Ans. Area of kite OAPB = 1728 cm²