If OA = 5 cm and OC = 3 cm, then find the length of AB. What is the name of two circles having a common
centre
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Answer:
Given OA=5CM
OM=3CM
∠OMA=
90
˚
So by Pythagoras theorem,
AM
2
=OA
2
−OM
2
AM
2
=5
2
−3
2
AM=4cm
We know that perpendicular from centre bisects the chord
Therefore AB=2AM
AB=8cm
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