Math, asked by sonusonam2211, 4 months ago

if OA=5cm,AB=8cm and OD is perpendicular to AB, then CD is equal to​

Answers

Answered by achint2035
22

Answer:

Hope It will clear

Step-by-step explanation:

We know that, the perpendicular from the centre of a circle to a chord bisects the chord.

AC = CB = 1/2 AB = 1/2 x 8 = 4 cm

given OA = 5 cm

AO2 = AC2 + OC2

(5)2 = (4)2 + OC2

25 = 16 + OC2

OC2 = 25-16 = 9

OC = 3 cm

[taking positive square root, because length is always positive]

OA = OD [same radius of a circle]

OD = 5 cm

CD = OD – OC = 5 – 3 = 2 cm

Answered by tanvi1307
6

Answer:

(a) We know that, the perpendicular from the centre of a circle to a chord bisects the chord.

AC = CB = 1/2 AB = 1/2 x 8 = 4 cm

given OA = 5 cm

AO2 = AC2 + OC2   

(5)2 = (4)2 + OC2

25 = 16 + OC2

OC2 = 25-16 = 9

OC = 3 cm

[taking positive square root, because length is always positive]

OA = OD [same radius of a circle]

OD = 5 cm

CD = OD – OC = 5 – 3 = 2 cm

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