Question

If OA=i+j+k, AB = 3i – 2j+k, BC=i+2j–2k and CD=2i+j+3k then find the vector OD.
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Answer 1

Answer:

OD＝7i+2j+3k

Step-by-step explanation:

OD

＝OA+AB+BC+CD

＝(i+j+k)+(3i-2j+k)+(i+2j-2k)+(2i+j+3k)