if OA.OB=OC.OD then show that A=C and B=D
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Answer:
Hence proved...
Step-by-step explanation:
OA . OB = OC . OD.
Show that ∠A =∠C and ∠B =∠D.
OA . OB = OC . OD (Given)
So, OA/OC=OD/OB .... (1)
Also, we have ∠AOD =∠COB (Vertically opposite angles) ...... (2)
Therefore, from (1) and (2), ΔAOD ~ ΔCOB (SAS similarity criterion)
So, ∠A = ∠C and ∠D =∠B
(Corresponding angles of similar triangles)
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