Question

If object is put at a distance of 10 cm from the focus of a convex lens of 20 cm, what will be the distance of the real image formed by the lens?

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Answer 1

Answer:

The image formed will be lesser than 10cm

Explanation:

Answer 2

Given,

• Initial Distance (u) = - (10+20) = -30 cm
• Focal Length (f) = 20 cm
• Final Distance (v) = ?

We know the Mirror Formula:

$\boxed{\bold{\sf{\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}}}}$

Applying the values to the equation:

$\sf{\implies \dfrac{1}{v}-\dfrac{-1}{30}=\dfrac{1}{20}}$

$\sf{\implies \dfrac{1}{v}+\dfrac{1}{30}=\dfrac{1}{20}}$

$\sf{\implies \dfrac{1}{v}=\dfrac{1}{20}-\dfrac{1}{30}}$

$\sf{\implies \dfrac{1}{v}=\dfrac{30-20}{20\times 30}}$

$\sf{\implies \dfrac{1}{v}=\dfrac{10}{600}}$

$\sf{\implies \dfrac{1}{v}=\dfrac{1}{60}}$

$\sf{\implies v=60 \ cm}$

$\boxed{\bold{\sf{\therefore \ Distance \ of \ real \ image \ formed \ by \ the \ lens = 60 \ cm}}}$