If observed dipole moment and calculated dipole moment is given then what is the % ionic charactor formula
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The calculated dipole moment is charge on electron * radius of molecule
That's off a bit, the calculated dipole moment (calculated assuming one electron has been completely transferred from hydrogen to bromine) is dependent on the bond length (interatomic spacing), not the radius.
μ100%μ100%μ100%=electron charge×interatomic spacing=(1.6×10−19) C×(1.41×10−10) m=2.26×10−29 C mμ100%=electron charge×interatomic spacingμ100%=(1.6×10−19) C×(1.41×10−10) mμ100%=2.26×10−29 C m
As you point out,
% ionic character=[μobs][μ100 %]=[2.6×10−30][2.26×10−29]=0.12=12 %
That's off a bit, the calculated dipole moment (calculated assuming one electron has been completely transferred from hydrogen to bromine) is dependent on the bond length (interatomic spacing), not the radius.
μ100%μ100%μ100%=electron charge×interatomic spacing=(1.6×10−19) C×(1.41×10−10) m=2.26×10−29 C mμ100%=electron charge×interatomic spacingμ100%=(1.6×10−19) C×(1.41×10−10) mμ100%=2.26×10−29 C m
As you point out,
% ionic character=[μobs][μ100 %]=[2.6×10−30][2.26×10−29]=0.12=12 %
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Here's the formula
% Ionic Character
= (Observed μ / calculated μ) × 100
[Here, μ is dipole moment]
Hope it helps You...!!!
(^_^)
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