If odd number of G.M.s are inserted between two given quantities a and b, show that the middle G.M.=√(ab)
Answers
Answered by
2
Thus the middle G.M = √ ab
Step-by-step explanation:
a, g1, g2, g3 ----------- gn, gn+1, g2n -1, b
a & b ab = g1, g2n -1 = gn g2n .........= gn-1, gn+1 = gn^2
gn^2 = ab ------(1)
Taking square root on both sides of the equation.
√ gn^2 = √ ab
gn = √ ab
Thus the middle G.M = √ ab
Similar questions