if ⅓ of a number exceeds 2/7 by 1, find the number
Answers
Answered by
11
Hello !!!
Here is your answer.
Let the number be x.
Then, its 1/3 = x/3, and
2/7 of the same number = 2x/7
Given that ⅓ of number exceeds 2/7 of the number by 1....
So,
x/21 = 1
Therefore, x = 21.
Hence the number is 21.
Hope You Got It
Here is your answer.
Let the number be x.
Then, its 1/3 = x/3, and
2/7 of the same number = 2x/7
Given that ⅓ of number exceeds 2/7 of the number by 1....
So,
x/21 = 1
Therefore, x = 21.
Hence the number is 21.
Hope You Got It
Answered by
8
Heya !!
Let number be X.
1/3 of X = 1/3 × X = X/3
And,
2/7 of X = 2/7 × X = 2X/7.
According to question,
X/3 = 2X/7 + 1
X/3 = 2X + 7/7
7X = 6X + 21
7X - 6X = 21
X = 21.
Hence,
Number = X= 21
★ HOPE IT WILL HELP YOU ★
Let number be X.
1/3 of X = 1/3 × X = X/3
And,
2/7 of X = 2/7 × X = 2X/7.
According to question,
X/3 = 2X/7 + 1
X/3 = 2X + 7/7
7X = 6X + 21
7X - 6X = 21
X = 21.
Hence,
Number = X= 21
★ HOPE IT WILL HELP YOU ★
RehanAhmadXLX:
:-)
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