Question

If [OH-] = 5.0*10.-5 M then pH will be

Answer 1

The pH is 9.

Ca(OH)2 - - - - - - - > Ca2+ + 2OH-

So,[OH-]=2×5×10^-6 M =10^-5

Therefore, pOH=5

Answer 2

$pH=9.7$ is the acidity of the base.

Explanation:

Given that:

molarity, $M=5\times 10^{-5}\ M$

We firstly find the pOH which is negative log of OH concentration.

$pOH=-log[OH^-]$

$pOH=-log[5\times 10^{-5}]$

$pOH=4.3$

So, the pH can be found by subtracting from 14.

$pH=14-4.3=9.7$

We find the basicity of an acid and acidity of a base to represent its strength.

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TOPIC: pH

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