= If [OH-] = 5.0 x 10-5 M then pH will be :- x (1) 5 - log 5 (2) 9 + log 5 (3) log 5 - 5 (4) log 5 - 9
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Answers
Answered by
6
Given that,
[OH
−
]=5×10
−5
M
pOH=−log[OH
−
]
pOH=−log[5×10
−5
]
pOH=5−log5
Now, pH=14−pOH
=14−(5−log5)
pH=9+log5
Explanation:
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Answered by
1
Answer:
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Explanation:
The correct answer is 14 so it is the strong base or alkaline.
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