Question

. If omega is a complex cube root of unity, then
the value of

{Check the image}

(a)-1
(b)1
(c)0
(d) None​

Answer 1

Correct Answer (c) 0

Pls refer to the attachment :)

Here,

Given, Omega is the cube root of unity..

1 + w + w^2 = 0

Since C1= 0,

The resulting determinant = 0.

By the theorem,

If each entry in a row ,or each entry in any column of a determinant is 0, then the determinant is equal to 0.

Answer 2

$\boxed{\mathsf{ \green{Answer}}}$

0

$\boxed{\mathsf{ \green{Explanation}}}$

Given:

omega is a complex cube root unity

To Find:

Value of the given determinant

Solution:

Refer the attachment!

$\texttt{ \blue{Aravind}\: \red{Reddy}....}$