Question

if on dividing the polynomial f(x)= 2x^4-3x^2-ax+b by x-2 ,then find the remainder ​

Answer 1

$\mathtt{\red{By \:remainder \:theorm ,}}$

x - 2 = 0

x = 2

$\mathtt{\blue{Let's \:put\: it \:in \:f(x) .}}$

→ 2 ( 2 )⁴ - 3 ( 2 )² - a ( 2 ) + b

→ 32 - 12 - 2a + b

→ 20 - 2a + b

→ 2 ( 10 - a ) + b

Answer 2

Answer:

b=20-2a

Step-by-step explanation:

X-2=0

X=2

2x^4-3x^2-ax+b

So 2×2^4-3×2^2-a×2+b

2×16-3×4-2a+b

32-12-2a+b

20-2a+b

-2a+b=20

b=20-2a

b=20-2a is the reminder

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