If on giving 40 joule of heat to a system, work done on the system is 10 joule, what will be the change in internal energy of the system?
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sign convention
heat given to the system = +ve
heat released by the system = -ve
work done by the system = +ve
work done on the system = -ve
so,
applying first law of thermodynamics
dq=du+dw
40= du+(-10)
du= 50 joule
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