if on root is 3+√5 then quadratic equation will be
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Then the other root follows 3- root of 5 and and then use the formula to find the equation
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since irrational roots occur in pair then the other root is 3–√5
now we have both roots and we can find the equation by
(x–a)(x–b) = 0
[x–(3+√5)] × [x–(3–√5)] = 0
we have,
x^2 – 6x + 4.
now we have both roots and we can find the equation by
(x–a)(x–b) = 0
[x–(3+√5)] × [x–(3–√5)] = 0
we have,
x^2 – 6x + 4.
Sunandit:
thanks
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