if one angel of a parallelogram is 90°, show that each of its angles measure 90°
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Step-by-step explanation:
Consider ABCD be a parallelogram and measure of angle C is 90°. Thus, m∠A=m∠B=m∠C=m∠D=90°. Since, all the angles of the parallelogram are equal to 90, therefore ABCD is a rectangle, by the properties of rectangle. Hence proved.
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