if one angle of a cyclic quadrilateral is acute then the opposite angle is
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•The sum of the opposite angles in cyclic quadrilateral is 180 ∘
∴∠A+∠C=180 ∘
⇒4y+20−4x=180
⇒4y−4x=180−20
⇒4y−4x=160
⇒x−y=−40....... (i)
∠B+∠D=180 ∘
⇒3y−5−7x+5=180
⇒−7x+3y=180....... (ii)
★Multiplying equation (i) by 3, we obtain
⇒3x−3y=−120........ (iii)
★Adding equations (ii) and (iii), we obtain
⇒−7x+3x=180−120
⇒−4x=60
⇒x=−15
★By using equation (i), we obtain
⇒x−y=−40
⇒−15−y=−40
⇒y=−15+40=25
- ∠A=4y+20=4×25+20=120 ∘
- ∠B=3y−5=3×25−5=70 ∘
- ∠C=−4x=−4×−15=60 ∘
- ∠D=−7x+5=−7×−15+5=110°
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