Question

If one angle of a parallelogram is 21° less than twice the smallest angle, then the measure of the largest angle of a parallelogram is

Answer 1

Answer:

113°

Step-by-step explanation:

$Let \: the \: smallest \: angle \: be \:  x  \\ </p><p>then, \: the \: largest \: angle \: will \: be =180−x \\ </p><p>but, the \: same \: equals \: to [2x−21] \\ </p><p>so \: we \: have [2x−21]=180−x  \\ </p><p>3x=201 \\ </p><p>x=67</p><p></p><p>thus \: the \: largest \: angle \:  180−67=113 degree</p><p></p><p>$