Question

If one angle of a parallelogram is 24º less then twice the smallest angle, find all the angles of the parallelogram.

Answer 1

Let the smallest angle of the parallelogram be x and larger be y, then

The angles of the parallelogram are ;
x,y,x,y

According to the question ;
y = 2x-24

and ,
x+y+x+y = 360
2x+2y = 360
x+y = 180
y = 180-x

2x-24 = 180-x
3x = 204
x = 68°

y = 180-x
y = 180-68
y = 112°
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Hence the angles of the Parallelogram area :
68°,112°,68°,112°