Question

If one angle of a parallelogram is 36 degrees less than twice it’s adjacent angle, then find the angles of parallelogram

Answer 1

We know aum of adjacent sides of parallelogram =180°
Let the adjacent angle be x .
So
x+2x-36=180°
3x=180°+36°
3x=216
x=72
Another angle =180-72=108°
So the angles are 72,108,72,108.
Hope this helps :)

Answer 2

Answer:

Answer:

Given :-

One side of a parallelogram is 36 less than twice adjacent sides .

To Find :-

What is the angles .

Solution :-

» Let, one of the angle be x

» And, the other angle be 2x - 36

We know that,

★ The sum of adjacent sides = 180° ★

➣ According to the question,

⇒ x + 2x - 36° = 180°

⇒ 3x = 180° + 36°

⇒ 3x = 216°

⇒ x = $\sf\dfrac{\cancel{216°}}{\cancel{3}}$

➠ x = 72°

Hence, the other angles required :-

➟ One angles is 72°

➟ Other angle will be 2x - 36 = 2(72) - 36 = 108°

$\therefore$ The angles of parallelogram are 108°, 72°, 108° and 72° .

Let's us verify the answer,

We know that,

✪ Sum of four parallelogram = 360° ✪

⇒ 108° + 72° + 108° + 72° = 360°

⇒ 180° + 180° = 360°

➠ 360° = 360°

Hence, Verified .