Question

If one angle of a parallelogram is 70 , find the degrees of the remaining three angles.

Answer 1

Answer:

The other angles are 110, 110 and 70 degrees

Step-by-step explanation:

Consider a parallelogram ABCD such that AB || CD

Let ∠ABC be 70 °

Then the opposite angle ∠ADC will also be 70°

and the other two angles ( ∠DAB and ∠BCA ) are supplementary angle angle of ∠ABC and ∠ADC respectively

Therefore,

∠ABC + ∠DAB = 180

=> 70° + ∠DAB = 180°

=> ∠DAB = 180° - 70° => 110°

Therefore ∠DAB = 110°

Similarlly ∠BCA is 180° - 70° => 110°