If one angle of a parallelogram is a right angle prove that it is a rectangle
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let angle A be 90 so angleB will also be of 90 because of coresponding angle as well as angle C will be of 90 and angle D will be of 90 because opposite angle of a paralellogram are equal
In quadrilateral ABCD all angle are of 90 so it is a rectangle
In quadrilateral ABCD all angle are of 90 so it is a rectangle
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Answer:
Step-by-step explanation:
Consider ABCD be a parallelogram and measure of angle C is 90°.
Now, since ABCD is a parallelogram, then measure of angle will be equal to measure of angle A, that is
m∠C=m∠A=90° (Opposite angles of parallelogram are equal)
and m∠A+m∠B=180 (Corresponding angles)
⇒90+m∠B=180
⇒m∠B=90
Also, m∠B=m∠D=90°(Opposite angles of parallelogram are equal)
Thus, m∠A=m∠B=m∠C=m∠D=90°.
Since, all the angles of the parallelogram are equal to 90, therefore ABCD is a rectangle, by the properties of rectangle.
Hence proved.
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