If one angle of a parallelogram is right angle, prove that it is a rectangle.
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Step-by-step explanation:
ABCD is parallelogram
∴AB∣∣CD & AD∣∣BC of ∠A=90
then, ∠D=180o −90 o=90 o (o = degree)
& ∠D=∠B & ∠A=∠C
(opposite angle of parallelogram are equal & sum of adjacent angle of parallelogram =180 o
)
∴∠A=∠B=∠C=∠D=90 o
It is a rectangle.
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