Question

If one angle of a parallelogram is twice of its adjacent angle find the angles of the Parallelogram.

Answer 1

opposite angles of ||gram are equal<br />therefore, in ||gram ABCD<br />A° = C° and B° = D°<br />let A° be x<br />adjacent angle = B°= 2x<br /> NOW, A° + B° + C° + D° = 360° (angle sum property) --> x + 2x + x + 2x = 360 --> 6x = 360° --> x = 360°/6 --> x = 60° Therefore, angle x = A° = C° = 60° and angle 2x = B° = D° = 2 (60) = 120°

Answer 2

Given,
one angle of a parallelogram is twice of its adjacent angle.
We know that,
In a parallelogram,
opposite angles are equal.
Let the angles are x° , 2x° , x° , 2x°
sum of the angles = 360°
 x° + 2x° + x° + 2x° = 360°
6x° = 360°
x° = 60°
Therefore the angles are 60° , 120° , 60° , 120°.