If one angle of a triangle is 130 then find angle between the bisector of the other
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Let three angles of the triangle are A, B and C
Let C= 130 (One angel is given as 130)
Then A+B = 180-130 = 50 (since A+B+C = 180)
Now
C + A/2 + B/2 = 180 (A/2 and B/2 are the bisector)
=> C + (A+B)/2 = 180
=> C + 50/2 = 180
=> C + 25 = 180
=> C = 180-25
=> C = 155
So the angle between the bisector of the other two angels is 155 degree
Let C= 130 (One angel is given as 130)
Then A+B = 180-130 = 50 (since A+B+C = 180)
Now
C + A/2 + B/2 = 180 (A/2 and B/2 are the bisector)
=> C + (A+B)/2 = 180
=> C + 50/2 = 180
=> C + 25 = 180
=> C = 180-25
=> C = 155
So the angle between the bisector of the other two angels is 155 degree
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