If one angle of a triangle is equal to one angle of the other triangle and sides including
these angles are proportional, then two triangles are similar.
Answers
Answered by
3
Step-by-step explanation:
Construction: Two triangles ABC and DEF are drawn so that one of the angles of one triangle is equal to one of the angles of another triangle. Moreover, two sides included in that angle of one triangle are proportional to two sides included in that angle of another triangle. This means;
∠ A = ∠ D and
A
B
D
E
=
A
C
D
F
theorem on similarity of triangles
To Prove: Δ ABC ∼ Δ DEF
Draw PQ in triangle DEF so that, AB = DP and AC = DF
Proof:
Δ
A
B
C
≅
Δ
D
P
Q
Because corresponding sides of these two triangles are equal
A
B
D
E
=
A
C
D
F
given
∠ A = ∠ D
Hence;
A
B
D
E
=
B
C
E
F
from SSS criterion
Hence;
A
B
D
E
=
A
C
D
F
=
B
C
E
F
Hence; Δ ABC ∼ Δ DEF proved
Answered by
2
Answer:
ye wala answer correct hai.
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