Question

If
one angle of a triangle is equal to one angle of the other
triangle and the sides including these angles are proportional, then the two
triangles are similar.​

Answer 1

Answer:

by ASA criteria

Step-by-step explanation:

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Answer 2

$\sf\small\underline\blue{Given:-}In ∆ABC and ∆DEF$

$\frac{ab}{de} = \frac{ac}{de} ( < 1)$

$And$

$= > \_A = \_D$

$\sf\small\underline\blue{RTP:-}$

∆ABC ~ ∆DEF

$\sf\small\underline\blue{Construction:-}$

Locate points P and Q on DE and DF respectively such that AB = DP and AC = DQ. Join PQ.

$\sf\small\underline\blue{Proof:-}$

PQ|| EF and ∆ABC~=∆DPQ

So \_A =\_D,\_B = \_P , \_C = \_Q

$\tt\large\boxed{∆ABC~ ∆DEF}$