if one angle of a triangle is equal to the sum of the other two angle also one of the angle is one third of the largest angle find the angles of a triangle.
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let the three angles of triangle be
x , y , and z.
one angle = sum of other 2 Angles
x = y + z ---(1)
let y = 1/ 3rd of the largest angle
y = 1/ 3 rd of x = x / 3
y = x / 3. ---(2)
sum of all the angles of triangle = 180°
x + y + z = 180°
x + x / 3 + z = 180
3x + x + 3z = 540
4x + 3z = 540 -------(3)
from (1) x = y + z =>
z = x - y = x - x / 3 = 2x/ 3
thus z = 2x / 3 ------(4)
put value of z in eq.(3), we get
4x + 3( 2x/ 3) = 540
6x = 540 => x = 90°
from(2)
y = x / 3 = 90 / 3 = 30°
from(4)
z = 2x / 3 = 2(90)/ 3 = 60°
therefore, x = 90° , y = 30° , z = 60°
Answer:
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all the angles of triangle are 90°, 30° and 60°.
x , y , and z.
one angle = sum of other 2 Angles
x = y + z ---(1)
let y = 1/ 3rd of the largest angle
y = 1/ 3 rd of x = x / 3
y = x / 3. ---(2)
sum of all the angles of triangle = 180°
x + y + z = 180°
x + x / 3 + z = 180
3x + x + 3z = 540
4x + 3z = 540 -------(3)
from (1) x = y + z =>
z = x - y = x - x / 3 = 2x/ 3
thus z = 2x / 3 ------(4)
put value of z in eq.(3), we get
4x + 3( 2x/ 3) = 540
6x = 540 => x = 90°
from(2)
y = x / 3 = 90 / 3 = 30°
from(4)
z = 2x / 3 = 2(90)/ 3 = 60°
therefore, x = 90° , y = 30° , z = 60°
Answer:
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all the angles of triangle are 90°, 30° and 60°.
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