If one angle of a triangle is greater than the sum of the other two, show
that the triangle is obtuse angled triangle
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Step-by-step explanation:
Consider ABC as a triangle
According to the question it can be written as ∠B > ∠A + ∠C …. (1)
We know that the sum of all the angles in a triangle is 180°.
So we can write it as ∠A + ∠B + ∠C = 180°
So we get ∠A + ∠C = 180° – ∠B
Substituting ∠A + ∠C in equation (1)
we get ∠B > 180° – ∠B
Add ∠B to both the sides of the equation
So we get ∠B + ∠B > 180o – ∠B + ∠B
By addition we get 2 ∠B > 180°
By division we get ∠B > 180/2 ∠B > 90°
So we know that ∠B > 90°
which means that ∠B is an obtuse angle
Therefore, it is proved that the triangle ABC is obtuse angled.
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