If one angle of parallelogram is 65°. Find other three angles.
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hope it helps..........
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heyyyy mate....
here is your answer
let abcd be a parallelogram
let angle a be 65°
angle c = angle a = 65°
[opposite angles of a parallelogram are equal]
angle a + angle b =180°
[adjacent angles of a parallelogram are supplementary]
therefore,
65+angle b =180
angle b = 180 - 65
angle b = 115°
angle b = angle d = 115°
[opposite angles of a parallelogram are equal]
therefore,
angle a = 65
angle b = 115
angle c = 65
angle d = 115
hope it helps you...!!!
here is your answer
let abcd be a parallelogram
let angle a be 65°
angle c = angle a = 65°
[opposite angles of a parallelogram are equal]
angle a + angle b =180°
[adjacent angles of a parallelogram are supplementary]
therefore,
65+angle b =180
angle b = 180 - 65
angle b = 115°
angle b = angle d = 115°
[opposite angles of a parallelogram are equal]
therefore,
angle a = 65
angle b = 115
angle c = 65
angle d = 115
hope it helps you...!!!
pala24:
hi
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