if one angle of triangle is 60 degree and other two angle are in the ratio 1:2 find the angels
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Answered by
0
Answer:
From the triangle ABC
Consider ∠A=60 degrees, ∠B:∠C=5:7
In a triangle
∠A+∠B+∠C=180 degrees
Substituting the values
60∘ +∠B+∠C=180
By further calculation
∠B+∠C=180 ∘ –60 ∘ =120 ∘
Take ∠B=5x and ∠C=7x
Substituting the values
5x+7x=120 ∘
12x=120 ∘
x=120 ∘ /12=10 ∘
So we get
∠B=5x=5×10 ∘ =50 ∘
∠C=7x=7×10 ∘ =70 ∘
Hope it helps you!!!
Answered by
0
Answer:
THE ANSWER IS 40 AND 80
Step-by-step explanation:
SUM OF ALL ANGLES IN A TRIANGLE = 180
FIRST ANGLE = 60
SUM OF REMAINING ANGLE = 180- 60
= 120
LET THE RATIO CONSTANT BE x
ratio is 1x+2x
ATQ
1X+2X= 120
3X=120
X= 120/3
X=40
SECOND ANGLE = 1 * 40 = 40
THIRD ANGLE = 2*40 = 80
FOR CHECKING
40 + 80 +60 = 180 DEGREE
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