If one angle of triangles is 130°, find the angle between the bisectors of the other two angles
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Answered by
20
Let the x and y be the bisected angles
so in the original triangle sum of angles is
130 + 2x + 2y = 180
=> 2(x+y) = 50
=> x + y = 25
so in the original triangle sum of angles is
130 + 2x + 2y = 180
=> 2(x+y) = 50
=> x + y = 25
Answered by
1
Answer:
Step-by-step explanation:
Consider a △ABC,such that ∠BAC=130
∘
and bisectors of ∠B and ∠C meet at O.
To find: ∠BOC
Now, in △ABC,
∠BAC+∠ABC+∠ACB=180
130+∠ABC+∠ACB=180 (Angle sum property)
∠ABC+∠ACB=50
2
1
(∠ABC+∠ACB)=25
∠OBC+∠OCB=25 (OB and OC bisect ∠ABC and ∠ACB)
Now, in △OBC,
∠OBC+∠OCB+∠BOC=180
25+∠BOC=180
∠BOC=155
∘
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