Question

If one base angle B of an isosceles triangle is 55° and the side AB = side AC, then find its vertex angle A .

Answer 1

Answer:

70

Step-by-step explanation:

AB=AC

Angle B= Angle C

angle B= angle C

55+55+x=180

110+x=180

x=70

please make me brainlist

Answer 2

By inequalities in a triangle
Angle C= Angle B
Hence angle C = 55°
By angle sum property angle A + angle B +angle C = 180
55°+55° + angle A =180
Angle A =180-(55+55)
=180-110
=70

Hence angle A =70°