Question

If one card is selected at random from a deck of 52 playing cards, what is the probability that the card is a club or a face card or both?​

Answer 1

Step-by-step explanation:

we don’t need to worry about that.

I’d we define face cards as King, Queen, Jack, there are 12 of them, as there are 4 suits.

There are 13 diamonds, 1/4 of 52.

3 of them are face cards, and are counted already.

So then there are 10 non-face diamonds.

10 diamonds + 12 face cards = 22 total, out of 52 in the deck.

22/52 = 11/26 is the probability

hope it helps :)

Answer 2

Answer:

p(club)or p(face)or p(club and face)=

$\frac{7}{13}$

Step-by-step explanation:

probability of drawing club card ♣️ =

$\frac{number \: of \: club \: cards}{total \: number \: of \: cards}$

=

$\frac{13}{52}$

probability of drawing face card =

$\frac{number \: of \: face \: cards}{total \: number \: of \: cards}$

=

$\frac{12}{52}$

probability of both club and face =

$\frac{3}{52}$

then probability that the card is club or face card or both = p(club)+p(face)+p(club and face)

=

$\frac{13}{52} + \frac{12}{52} + \frac{3}{52} = \frac{13 + 12 + 3}{52} = \frac{14}{26} = \frac{28}{52} \\ = \frac{7}{13}$

#SPJ2