Question

if one coin and one die are thrown simultaneously then find the probability of getting head and an odd number

Answer 1

there are two total probabilities in tossing coin
so ans of getting head is 1/2

and there are 3 probabilities 1,3,d 5 so its probability is 3/6 =1/2

Answer 2

Answer: The required probability is $\dfrac{1}{4}$

Step-by-step explanation:

If a coin and a die is thrown simultaneously then the possible outcomes will be {1 H, 2 H , 3 H , 4 H, 5 H, 6 H, 1 T, 2 T, 3 T, 4 T, 5 T, 6 T}

Now E is the event

E: Getting an odd number and head= {1 H, 3 H ,5 H}

As we know

$P(E)= \dfrac{\text {Number of favourable outcomes}}{\text {Total outcomes}}$

Total outcomes = 12

Favourable outcomes = 3

$P(E)= \dfrac{3}{12} =\dfrac{1}{4}$

Hence , the required probability is $\dfrac{1}{4}$