If one diagonal cuts the other diagonal in the ratio of 1:3 in a trapizium prove that one of the parallel sides is 3 times greater than the other
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In Δ AOC and Δ DOC
∠AOB = ∠COD
OBA = ODC(DB is transversal)
ΔAOC≈ΔDOC
AO/OC = AB/DC
AB/DC = 3/1
AB=3DC
∠AOB = ∠COD
OBA = ODC(DB is transversal)
ΔAOC≈ΔDOC
AO/OC = AB/DC
AB/DC = 3/1
AB=3DC
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