If one diagonal of a square is along the line 8x-15y=0and one of its vertex is at (1,2) then find the equation of the sides of the square passing through this vertex
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Let ABCD be the given square and the coordinates of the vertex D be 1 2. We are required to find the equations of its sides DC and AD.Given that BD is along the line 8x - 15y = 0 so its slope is 8/15. The angles made by BD with sides AD and DC is 45°. Let the slope of DC be m. Thenor 15 + 8m = 15m – 8or 7m = 23 which gives m =23/7Therefore the equation of the side DC is given bySimilarly the equation of another side AD is given by.
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