If one diagonal of square is along the line 8x-15y=0 and one of its vertex is at (1,2) then find the equations of sides of square passing through this vertex..
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Let ABCD be the given square and the coordinates of the vertex D be (1, 2). We are required to find the equations of its sides DC and AD.
Given that BD is along the line 8x - 15y = 0, so its slope is 8/15. The angles made by BD with sides AD and DC is 45°. Let the slope of DC be m. Then
or 15 + 8m = 15m – 8
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