) If one die thrown, then find the probability of getting:
a) an even prime number
b) 7
c) a 1, a 2, a 3, a 4
d) an odd numbers
Answers
Answer:
a)1/6
b)0
c)4/6=2/3
d)3/6=1/2
Step-by-step explanation:
HOPE IT'S CORRECT :)
Answer:
a) Let E = Getting a prime number
No. of Favorable Outcomes = 1 ( Since there is only 1 even prime ).
No. of Possible Outcomes = 6 ( When a die is rolled we are bound to get any of the 6 numbers ) .
P(E) = No. of Favorable Outcomes / No. of Possible Outcomes
= 1 / 6 ...( If u wish you can convert it into percentage by multiplying with 100)
b) The number 7 isn't present on the die.
Therefore , it is an impossible event .
( If you are writing in your classwork or preparing for an exam , go for the same format I've used in the a) bit . It will fetch you more marks. )
c) Since the number 1 is present only once on a die , the probability of getting 1 will be 1/6 . Same goes for 2 , 3 and 4.
d) There are 3 odd numbers from 1 to 6 i.e. 1,3 and 5.
Possible outcomes are 6 as usual .
So the probability of getting an odd no. is 3/6 = 1/2.
Hope it helps
Mark as Brainliest
Regards
PrincessAZ